4=(6x+1)^1/2-(17-4x)^1/2

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Solution for 4=(6x+1)^1/2-(17-4x)^1/2 equation: 


x in (-oo:+oo)

4 = ((6*x+1)^1)/2-(((17-(4*x))^1)/2) // - ((6*x+1)^1)/2-(((17-(4*x))^1)/2)

((17-(4*x))^1)/2-(((6*x+1)^1)/2)+4 = 0

(17-4*x)/2-((6*x+1)/2)+4 = 0

(-1*(6*x+1))/2+(17-4*x)/2+4 = 0

(-1*(6*x+1))/2+(17-4*x)/2+(2*4)/2 = 0

2*4-1*(6*x+1)-4*x+17 = 0

8-10*x+16 = 0

24-10*x = 0

(24-10*x)/2 = 0

(24-10*x)/2 = 0 // * 2

24-10*x = 0

24-10*x = 0 // - 24

-10*x = -24 // : -10

x = -24/(-10)

x = 12/5

x = 12/5

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